Hello everybody! This is Alex :) I am scribing today, so lets get started.
Today was a work period so there isn't a lot to say. We had to finish our lab report, once we did that we were required to read page 8 of the white booklet Ms. Kozoriz (sorry if I spelled that wrong) gave us. Once we did that we had to do 4 worksheets. Sorry I don't have a scanner so I can't scan them onto this blog, however they were fairly easy just remember Newton's second law (a=Fnet/m) and Fnet= Fg + Fn. Fg= (m)*(g).
So that was basically it. I hope everyone has a wonderful Holiday and stays warm, see you tomorrow.
For the next post I don't know how the choosing process works so....... um how about Mark. Ms. Kozoriz can change it if she wants.
Wednesday, December 17, 2008
Tuesday, December 16/08
Sorry for the late post, for thsoe who check this blog regularly, I kinda forgot and just remebered this morning. Well Yesterday we didnt do much. We learned about the weight and scale and how it REALLY feels when you move it up or down. We were also given a Lab to do which is probably due today if anyone is unsure.
Heres the notes she gave us, please make sure to correct me if I'm wrong because I'm writing this based on memory.Also sorry that I can't post any diagrams to explain this better.
F=mg
At this point the weight is at rest so it will feel normal.
F=mg + ma
You move the weight and scale along with it up and this is how it will feel...
It will become heavier at first then at a constant velocity you will feel normal. Then as you start to slow down as you reach the end the weight then becomes lighter.
F=mg -ma
This one is opposite direction with the opposite affect. You feel light at first as you move the weight and scale in the downward direction, then at constant velocity it feels normal. When you the start to slow down towards the end it will then become heavy.
*NOTE* When I say it feels normal it just means you can't tell if it got heavier or lighter then before.
The Lab...
For those who were confused on what they needed to do
What we had to do was get a rubber thingy(don't rember what its called) and tie to to a piece of string that is about 1.5 m's long. You then shorten the string by rolling in your hand to get 1.2m, 1.0m, 0.8m, 0.6m, 0.4m ,0.2m. These are the different lengths that you will be measuring how much time its takes for it to swing twenty cycles( one cycle equals the time it takes for it to come back from where you started it. Remember to start the rubber stopper up to the right of you and keep hand still will doing experiment. Its quite annoying to hold all the time so switch places with your partner if your arm feel tired. Record all the data 3 times each. Then average your time. The period is calculated by the (average time/20 cycles it did). Of course do the Analysis questions after you have completed this experiment and dont forget to hand in.
Sorry once again for the late post as I COMPLETELY FORGOT even though I was told before hand. :S
The next scribe I choose will be Alex Sharp. So good luck Alex with next scribe.
Heres the notes she gave us, please make sure to correct me if I'm wrong because I'm writing this based on memory.Also sorry that I can't post any diagrams to explain this better.
F=mg
At this point the weight is at rest so it will feel normal.
F=mg + ma
You move the weight and scale along with it up and this is how it will feel...
It will become heavier at first then at a constant velocity you will feel normal. Then as you start to slow down as you reach the end the weight then becomes lighter.
F=mg -ma
This one is opposite direction with the opposite affect. You feel light at first as you move the weight and scale in the downward direction, then at constant velocity it feels normal. When you the start to slow down towards the end it will then become heavy.
*NOTE* When I say it feels normal it just means you can't tell if it got heavier or lighter then before.
The Lab...
For those who were confused on what they needed to do
What we had to do was get a rubber thingy(don't rember what its called) and tie to to a piece of string that is about 1.5 m's long. You then shorten the string by rolling in your hand to get 1.2m, 1.0m, 0.8m, 0.6m, 0.4m ,0.2m. These are the different lengths that you will be measuring how much time its takes for it to swing twenty cycles( one cycle equals the time it takes for it to come back from where you started it. Remember to start the rubber stopper up to the right of you and keep hand still will doing experiment. Its quite annoying to hold all the time so switch places with your partner if your arm feel tired. Record all the data 3 times each. Then average your time. The period is calculated by the (average time/20 cycles it did). Of course do the Analysis questions after you have completed this experiment and dont forget to hand in.
Sorry once again for the late post as I COMPLETELY FORGOT even though I was told before hand. :S
The next scribe I choose will be Alex Sharp. So good luck Alex with next scribe.
Monday, December 15, 2008
Howdy Fellow Bloggers!
Today we didn't do much of anything that is new.
What we did was work more on the lab worksheet we were given on December 12, aka Friday. I believe that is due tomorrow, but that is just an assumption.
We were also given the answers for "Concept-Development Practice Page 13-1 -- Chapter 13: Gravitational Interactions", so here they are:
1. An apple that has a mass of 0.1kg has the same mass wherever it is. The amount of matter that makes up the apple
DOES NOT DEPEND UPON
the location of the apple. It has the same resistance to acceleration wherever it is -- its inertia everywhere is
THE SAME.
The weight of the apple is a different story. It may weigh exactly 1N in San Fransisco and slightly less in mile high Denver, Colorado. On the surface of the moon the apple would weigh 1/6N, and far out in outer space it may have almost no weight at all. The quantity that doesn't change with location is
MASS,
and the quantity that may change with location is its
WEIGHT.
That's because
WEIGHT
is the fore due to gravity on a body, and this force caries with distance. So weight is the force of gravity between two bodies, usually some small object in contact with the earth. When we refer to the
WEIGHT
of an object we are usually speaking of the gravitational force that attracts it to the earth.
2. If we stand on a weighing scale and find that we are pulled toward the earth with a force of 500N, the we weight 500N. Strictly speaking, we weight 500N relative tot he earth. How much does the earth weight? If we tip the scale upside down and repeat the weighing process, we can say that we and the earth are still pulled together with a force of 500N, and therefore, relative to us, the whole 6 000 000 000 000 000 000 000 000-kg earth weighs 500N! Weight, unlike mass, is a relative quantity.
Hmm, that seems to be it.
OH, also, if you are bored read pages 5 and 6 for tomorrows class in the Dynamics booklet. And tomorrow we have another lab, so don't miss it!
The scribe for tomorrow shall be... Anthony L!
Toodles!
What we did was work more on the lab worksheet we were given on December 12, aka Friday. I believe that is due tomorrow, but that is just an assumption.
We were also given the answers for "Concept-Development Practice Page 13-1 -- Chapter 13: Gravitational Interactions", so here they are:
1. An apple that has a mass of 0.1kg has the same mass wherever it is. The amount of matter that makes up the apple
DOES NOT DEPEND UPON
the location of the apple. It has the same resistance to acceleration wherever it is -- its inertia everywhere is
THE SAME.
The weight of the apple is a different story. It may weigh exactly 1N in San Fransisco and slightly less in mile high Denver, Colorado. On the surface of the moon the apple would weigh 1/6N, and far out in outer space it may have almost no weight at all. The quantity that doesn't change with location is
MASS,
and the quantity that may change with location is its
WEIGHT.
That's because
WEIGHT
is the fore due to gravity on a body, and this force caries with distance. So weight is the force of gravity between two bodies, usually some small object in contact with the earth. When we refer to the
WEIGHT
of an object we are usually speaking of the gravitational force that attracts it to the earth.
2. If we stand on a weighing scale and find that we are pulled toward the earth with a force of 500N, the we weight 500N. Strictly speaking, we weight 500N relative tot he earth. How much does the earth weight? If we tip the scale upside down and repeat the weighing process, we can say that we and the earth are still pulled together with a force of 500N, and therefore, relative to us, the whole 6 000 000 000 000 000 000 000 000-kg earth weighs 500N! Weight, unlike mass, is a relative quantity.
Hmm, that seems to be it.
OH, also, if you are bored read pages 5 and 6 for tomorrows class in the Dynamics booklet. And tomorrow we have another lab, so don't miss it!
The scribe for tomorrow shall be... Anthony L!
Toodles!
Friday, December 12, 2008
Dec 12 blog
Hey everyone!
Well today in class we got our Newton's Laws of Motions test back, and Ms.K went over the answers for it. So here are the answers:
1. gravitational, electromagnetic, strong nuclear, weak nuclear
2. The coin will land at your feet because it has the same velocity as the bus.
3. The net force would equal zero.
4. Normal force, gravitational force.
5. 75 N
6. It shows the forces acting on an object.
7.
8 a) acceleration will double
br) acceleration will double
c) 1/8 the acceleration
9.a) 4.oN [S]
b)7.8 [at 40° north of east]
10. a=Fnet/m
= 9.50N[S]/20.0Kg
= 0.475m/s² [S]
b) V=(A)(t)
=(o.475m/s²)(1.86s)
= 0.884m/s[S]
11. a=Fnet/m
= 3.2N[E]/ 6.0Kg
= o.533m/s²[E]
12. a=V/t Fnet=(a)(m)
=8.0m/s /1.5s =(5.33m/s²)(110Kg)
= 5.33m/s² = 586N
13.a) b)
After correctin our test we read through the booklet on Gravitational Fields. Then we got 2 sheets, The Elevator Ride and Force and Weight Concept Development. We worked on the Elevator Ride lab for the rest of the class and we will finish it up on monday.
Have a good weekend!! The next scribe will be Nicole. : )
Good Morning bloggers
well its a new beautiful day today! well in class yesterday, thursday the 11th, (sorry about my spelling and what not) we had our dynamics test!! woot! it was pretty simple test and i don't know what else to say. O ya! Ms.K gave us that new booklet of notes that we should read before today's class. I think that's all we did? test and the new book for the new unit? ya?alrity then cya all in class!! next scribe is rebecca.
Wednesday, December 10, 2008
Class on Wednesday, December 10, 2008
I'll revive this fairly deceased blog by re-initiating scribing. *cough* bonus marks *cough* I mean there is a test tomorrow on the unit, dynamics - a branch of mechanics that deals with forces and their relations to patterns of motion. I posted the sheet consisting of anagrams because it was from the past and no one was blogging for quite a while. Okay, so euphemistically, there is a lovely and highly admired test tomorrow. Good luck to everyone. There is an immaculate review below as posted by our teacher to remedy any difficulties that one may stumble upon while writing the test. Below are sheets I scanned, so feel free to browse.
remember that there is no air resistance when a rock is in free fall. that was my first instinct but then i asked for the opinions of others
for 8b) Ms. K said the answer being force RESISTING the car's motion was 3740N, but I still object. The force of the car caused by acceleration is 3740N as calculated by multiplying the mass and acceleration. To further justify, it states that the force put on the wheels due to the road is 5600N, which is a frictional force and what we are trying to find is the resisting force being the force impeding the car. So I obtain the difference between the two resultant forces which results in 1860 N [East]. Friction resists, so this is the resisting force.
We went through the sheets above and received back our assignment on vectors. Well this is a fairly accurate summation of class today. I dub the next scribe Sir Dion Palumbo. He's a lucky duck to be the scribe for the day of the test. Thou shall scribe effortlessly because of the sympathetic initiator.
Thursday, December 4, 2008
Force And Acceleration Lab
Hi there!
Sorry I forgot to blog yesterday.
Anyway, here's the lab that we did yesterday and today:
First of all we should know the Newton's laws;
First Law - When no net external force is acting on an object, it will either remain at rest or if it is moving, it will continue to move in a straight line at a constant speed.
Second Law - If an unbalanced force acts on an object, the object will undergo an acceleration directly proportional to the magnitude of the force.
Equipment:
Recording Timer
Washers
Lab Cart
Paper clips
Carbon Paper Discs
Pulley
Long Flat board/surface
Timer Tape
String
50 g
100 g
200 g
Procedure:
1. Load the cart with the weights (50, 100 and 200 grams). Attaach one end of the string to the cart. Tie a paper clip to the other end of the string and pass it over the pulley. Hang the metal washers on the clip until the friction force acting on the cart is just offset. Forces due to friction are offset when you can give the cart a very slight push and it moves at a constant speed across the table. Do no removethe added weight at any time.
2. Pull the end of the timer tape through the timer and attach it to and end part of the cart. For the first trial, reemov the 50 g mass from the cart and hang it on the end of the string.
3. Star the timer and release the cart. Stop the timer and the cart when the cart reaches the pulley. Renove the timer tape and label it "50 g trial" on the end that was attached to the cart.
4. Remove the 50 g mass from the string and put it back on the cart. Remove the 100 g mass from the cart and place it on the end of the string. Make and label a second tape in the same way as you made the first tape.
5. Repeat steps 2 and 3 for 150 g, 200 g, and 250 g.(as a result increasing the mass by 50 g each time.) Be sure to place each mass on the cart after using it.
6. In this investigation, wour cart will in general undergo less acceleration than did those of prior investigations. For this reason, it is best to use a larger time interval than thoose used in earlier investigations. Label the first dot on each tape zero. Label every ffith dot after that 1, 2, 3, 4 and so on. The distance between two each numbered dots represents one time interval (a "tock"). The distance between each numbered dot is numerically the same as the avaerage velocity for each time interval. The distance is also numerically the same as the instantaneous velocity for the midpoint of the time interval. Measure each distance on each tape carefully and record al your values.
Interpretation:
1. On the same graph, make a velocity versus time plot for each tape. Plot veloccity on the vertical axis anad the time interval on the horizontal axis.
2. The slope of a velocity time graph is (Vf - Vi)/t, which is the acceleration. Determine the slope of each of the lines on your velocity-time(tock) graph. Record each value.
3. Plot a graph of acceleration versus force with force on the horizontal axis.
4. Explain the meaning of the graph. Does it substantiate Newton's second law?
The next blogger is Thoa:-)
Sorry I forgot to blog yesterday.
Anyway, here's the lab that we did yesterday and today:
First of all we should know the Newton's laws;
First Law - When no net external force is acting on an object, it will either remain at rest or if it is moving, it will continue to move in a straight line at a constant speed.
Second Law - If an unbalanced force acts on an object, the object will undergo an acceleration directly proportional to the magnitude of the force.
Equipment:
Recording Timer
Washers
Lab Cart
Paper clips
Carbon Paper Discs
Pulley
Long Flat board/surface
Timer Tape
String
50 g
100 g
200 g
Procedure:
1. Load the cart with the weights (50, 100 and 200 grams). Attaach one end of the string to the cart. Tie a paper clip to the other end of the string and pass it over the pulley. Hang the metal washers on the clip until the friction force acting on the cart is just offset. Forces due to friction are offset when you can give the cart a very slight push and it moves at a constant speed across the table. Do no removethe added weight at any time.
2. Pull the end of the timer tape through the timer and attach it to and end part of the cart. For the first trial, reemov the 50 g mass from the cart and hang it on the end of the string.
3. Star the timer and release the cart. Stop the timer and the cart when the cart reaches the pulley. Renove the timer tape and label it "50 g trial" on the end that was attached to the cart.
4. Remove the 50 g mass from the string and put it back on the cart. Remove the 100 g mass from the cart and place it on the end of the string. Make and label a second tape in the same way as you made the first tape.
5. Repeat steps 2 and 3 for 150 g, 200 g, and 250 g.(as a result increasing the mass by 50 g each time.) Be sure to place each mass on the cart after using it.
6. In this investigation, wour cart will in general undergo less acceleration than did those of prior investigations. For this reason, it is best to use a larger time interval than thoose used in earlier investigations. Label the first dot on each tape zero. Label every ffith dot after that 1, 2, 3, 4 and so on. The distance between two each numbered dots represents one time interval (a "tock"). The distance between each numbered dot is numerically the same as the avaerage velocity for each time interval. The distance is also numerically the same as the instantaneous velocity for the midpoint of the time interval. Measure each distance on each tape carefully and record al your values.
Interpretation:
1. On the same graph, make a velocity versus time plot for each tape. Plot veloccity on the vertical axis anad the time interval on the horizontal axis.
2. The slope of a velocity time graph is (Vf - Vi)/t, which is the acceleration. Determine the slope of each of the lines on your velocity-time(tock) graph. Record each value.
3. Plot a graph of acceleration versus force with force on the horizontal axis.
4. Explain the meaning of the graph. Does it substantiate Newton's second law?
The next blogger is Thoa:-)
Tuesday, December 2, 2008
Video mr.same same
Hi! Everyone...it's me Larlyn014 your scribe for today's class...
Today!
We watch a video of mr. same same..I think that's what they call him....anyways...it's about Inertia force.
INERTIA FORCE
Today!
We watch a video of mr. same same..I think that's what they call him....anyways...it's about Inertia force.
INERTIA FORCE
- Inertia in other words mass
- Mass in other words Matter
Note: If you have an arrow with a bow then shot it. What's keeping the arrow moving? There's no any things that keeping it moving Inertia that make who make it move by itself.
Sorry that's the only I remember on what we just watch. And I remember there's another example he shows to prove things more clearly.
After watching that Mrs. Kozoris let us finished the worksheet she gave from yesterdays class.That's all for today.
Im really sorry I didn't explain things more clearly. I was trying to find video to clear things up and this is what I found
Here's another one.....example of Newton's First Law
THE INERTIA
Next scribe Intrepid ^_^
Monday, December 1, 2008
hello!!
Hello!! It's me Ramina Lyn..
today in class, we corrected the test, then we started the new lesson "Dynamics". Also we got 4 sheets about dynamic from Ms. k...
here's the correction...
1. Vector quantities
- position
- force
- displacement
- acceleration
- velocity
2. Measure initial and final velocities (add them) and then divide by two or Calculate total displacement divided by time.
3. constant (uniform)
4. a) 650 km
b) 150 km [E]
5. a) 108 km/h
b) 25 km/h [E] ---> 30 km/h [E]
6. a) +10 m
b) 0m
c) -40 m
d) 0m
7. a) +2m/s
b) 0m/s
8. a) Car moving at a constant (uniform) velocity of 0m/s
b) cars slowing down
c) 0m/s
d) -5 m/s2
9. +180 m/s
10. --> start a distance away from motion sensor , stand still
------> walk at a constant speed towards motion sensor and then past it
------> stand still
11. 5.0 m/s2
12. 1120 m
13. 28 m
14. 916. 67 m/h or 920 m/h
We also read the Four Fundamental Forces..
The four fundamental forces are: gravitational, electromagnetic, strong nuclear, and weak nuclear force.
Gravitational Force - an attraction between two objects because of their mass. It is the weakest of the foue force. Range is unlimited and attractive.Also the least selective because it acts between all particles.
Electromagnetic Force - the force that charged particles exert on each other. It binds together the atoms and molecules that make up the matter that we see around us. It can be either attractive or repulsive. It is much stronger than the gravitational force and its range is also unlimited.
Strong Nuclear Force - an attractive force that holds protons and neutrons in the nucleus of an atom. It is the strongest of the four force, but only acts over small distances.
Weak Nuclear Force - million times fainter than strong force and hundred times shorter in range. Much stronger than the gravitational force. It is involved in the radioactive decay of some nuclei. It has been linked with the electromagnetic force.
ok that's all we did today =)
the next scribe is larlyn...
today in class, we corrected the test, then we started the new lesson "Dynamics". Also we got 4 sheets about dynamic from Ms. k...
here's the correction...
1. Vector quantities
- position
- force
- displacement
- acceleration
- velocity
2. Measure initial and final velocities (add them) and then divide by two or Calculate total displacement divided by time.
3. constant (uniform)
4. a) 650 km
b) 150 km [E]
5. a) 108 km/h
b) 25 km/h [E] ---> 30 km/h [E]
6. a) +10 m
b) 0m
c) -40 m
d) 0m
7. a) +2m/s
b) 0m/s
8. a) Car moving at a constant (uniform) velocity of 0m/s
b) cars slowing down
c) 0m/s
d) -5 m/s2
9. +180 m/s
10. --> start a distance away from motion sensor , stand still
------> walk at a constant speed towards motion sensor and then past it
------> stand still
11. 5.0 m/s2
12. 1120 m
13. 28 m
14. 916. 67 m/h or 920 m/h
We also read the Four Fundamental Forces..
The four fundamental forces are: gravitational, electromagnetic, strong nuclear, and weak nuclear force.
Gravitational Force - an attraction between two objects because of their mass. It is the weakest of the foue force. Range is unlimited and attractive.Also the least selective because it acts between all particles.
Electromagnetic Force - the force that charged particles exert on each other. It binds together the atoms and molecules that make up the matter that we see around us. It can be either attractive or repulsive. It is much stronger than the gravitational force and its range is also unlimited.
Strong Nuclear Force - an attractive force that holds protons and neutrons in the nucleus of an atom. It is the strongest of the four force, but only acts over small distances.
Weak Nuclear Force - million times fainter than strong force and hundred times shorter in range. Much stronger than the gravitational force. It is involved in the radioactive decay of some nuclei. It has been linked with the electromagnetic force.
ok that's all we did today =)
the next scribe is larlyn...
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